测试派 Give testers a home.

因为之前有个作业是输出直角三角形，所以昨天抽空琢磨了下正三角形的输出，emmm还是先算出来规律才写的。。今天看到这个作业，又改动了下，为了加空格差点把自己绕进去😂 😂

if name == 'main':
num = int(input('input a number:'))
newLi = []
li = [x for x in range(1,num,2)]
if num % 2 != 0:
newLi = li + [num] +li[::-1]
else:
newLi = li + li[::-1]
print(newLi)
for i in newLi:
print(i*'*')

# 镜像星星金字塔
def mirror_star_pyramid(n):
    i = 1# 给定初始值
    star_list1 = []# 存正金字塔每一层元素
    star_list2 = []# 存倒金字塔每一层元素
    while i <= n:
        star_list1.append(' '*((n-i)//2) + '*'*i + ' '*((n-i)//2))
        # n的奇偶性将决定倒金字塔的元素是跟正金字塔一样还是比正金字塔少一层
        if n % 2:
            star_list2.append(' '*((i+1)//2) + '*'*(n-i-1) + ' '*((i+1)//2))
        else:
            star_list2 = star_list1[::-1]
        i += 2
    for each in star_list1:print(each)
    for each in star_list2:print(each)

if __name__ == '__main__':
    mirror_star_pyramid(5)
    mirror_star_pyramid(6)

# -*- coding: UTF-8 -*-
# @Author: Sai_Python12
# @Email: 932934045@qq.com
# @File: StarStar.py

class MyStar:
    '''星星类'''
    def __init__(self, n):
        self.n = n
        self.data_1 = [] #存放上半部左侧空格数量
        self.data_2 = [] #存放上半部星号数量

    def my_star(self):
        K = int((self.n+1)/2) #K 为上部一半
        for i in range(1, K+1):#i 为行数
            self.data_1.append(K-i)
            self.data_2.append(2*i-1)
            print(' '*self.data_1[i-1] + '*'*self.data_2[i-1])

        if self.n % 2 == 0:
            for i in range(1, K+1):
                print(' '*self.data_1[-i] + '*'*self.data_2[-i])
        else:
            for i in range(1, K):
                print(' '*self.data_1[-i-1] + '*'*self.data_2[-i-1])
        print(self.data_1)
        print(self.data_2)

if __name__ == '__main__':
    MyStar(6).my_star()