20200324 连接查询作业

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根据课上的emp和dept表完成下列作业:

  1. 查询张姓员工的员工信息和所在部门信息。
  2. 查询张三丰管理了几个员工
  3. 查询出所有实习员工(实习员工无部门信息)

建表语句

DROP TABLE IF EXISTS `emp`; CREATE TABLE `emp` ( `id` int(11) NOT NULL COMMENT '员工编号', `name` varchar(255) CHARACTER SET utf8 COLLATE utf8_general_ci NULL DEFAULT NULL COMMENT '员工姓名', `dept_id` int(11) NULL DEFAULT NULL COMMENT '部门编号', `leader` int(11) NULL DEFAULT NULL COMMENT '直属领导id', `is_enable` int(11) NULL DEFAULT NULL COMMENT '是否在职 1在职 0离职', PRIMARY KEY (`id`) USING BTREE ) ENGINE = InnoDB CHARACTER SET = utf8 COLLATE = utf8_general_ci ROW_FORMAT = Compact; INSERT INTO `emp` VALUES (1, '张三丰', 1, 0, 1); INSERT INTO `emp` VALUES (2, '张无忌', 1, 1, 1); INSERT INTO `emp` VALUES (3, '小龙女', 1, 1, 1); INSERT INTO `emp` VALUES (4, '小白菜', 1, 3, 1); INSERT INTO `emp` VALUES (5, '韦小宝', 2, 0, 1); INSERT INTO `emp` VALUES (6, '令狐冲', 2, 0, 1); INSERT INTO `emp` VALUES (7, '东方不败', 0, 8, 1); INSERT INTO `emp` VALUES (8, '任我行', 3, 0, 1); INSERT INTO `emp` VALUES (9, '李寻欢', 0, 8, 1); DROP TABLE IF EXISTS `dept`; CREATE TABLE `dept` ( `id` int(11) NOT NULL COMMENT '部门id', `name` varchar(255) CHARACTER SET utf8 COLLATE utf8_general_ci NULL DEFAULT NULL COMMENT '部门名称', PRIMARY KEY (`id`) USING BTREE ) ENGINE = InnoDB CHARACTER SET = utf8 COLLATE = utf8_general_ci ROW_FORMAT = Compact; INSERT INTO `dept` VALUES (1, '销售部'); INSERT INTO `dept` VALUES (2, '信息技术部'); INSERT INTO `dept` VALUES (3, '财务部'); INSERT INTO `dept` VALUES (4, '有关部门');

上课实战脚本

#交叉连接 select * from emp; #笛卡尔积 select * from emp,dept; select * from emp cross join dept; #内连接 #显示内连接,标准内连接 on 两张表如何关联 select * from emp as a inner join dept as b on a.dept_id = b.id; #隐式内连接 where 在结果集的基础上做条件筛选 select * from emp as a,dept as b where a.dept_id = b.id; #内连接 join 省略 inner select * from emp as a join dept as b on a.dept_id = b.id; #内连接 cross join select * from emp as a cross join dept as b on a.dept_id = b.id; # mysql cross join on inner join on 结果上没有区别 # 标准sql cross join 不能使用onmysql中支持on的操作。 #特殊内连接 不等值内连接 select * from emp as a inner join dept as b on a.dept_id > b.id; #特殊内连接 自连接 select * from emp as a inner join emp as b on a.id = b.leader; #外连接 #外连接显示的内容比内连接要多,内连接的补充 >= #左外连接,左表为主表右表为从表,主表所有数据都显示,从表只有匹配上的数据才显示 select * from emp as a left join dept as b on a.dept_id = b.id; #左外连接,右表为主表左表为从表,主表所有数据都显示,从表只有匹配上的数据才显示 select * from emp as a right join dept as b on a.dept_id = b.id; select * from dept as b left join emp as a on a.dept_id = b.id; #外连接 查询从表为空的数据 select * from emp as a left join dept as b on a.dept_id = b.id where b.id is null; # on(两张表如何关联)onwhere之前 where(结果集的基础上做条件筛选)的区别 select * from emp as a left join dept as b on a.dept_id = b.id where b.id is null; #全连接 full join #sql1 #UNION #sql2; #sql1 + sql2 select * from emp as a left join dept as b on a.dept_id = b.id union select * from emp as a right join dept as b on a.dept_id = b.id; # union all 不去重复 select * from emp as a left join dept as b on a.dept_id = b.id union all select * from emp as a right join dept as b on a.dept_id = b.id;
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luojie 在 2020-08-06 17:33:22 更新了该帖
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  • hh_1

    1、查询张姓员工的员工信息和所在部门信息。
    image.png

  • 其他回帖
  • zhongyh

    -- 根据课上的emp和dept表完成下列作业:
    -- 1、查询张姓员工的员工信息和所在部门信息。
    #判断以哪张表为基表,看最主要的是得到那张表的信息,或者要筛选的是哪那张表的信息
    SELECT * from emp e left JOIN dept d on e.dept_id =d.id where e.name like '张%';

    -- 2、查询张三丰管理了几个员工
    select count(*) from emp e1 INNER JOIN emp e2 on e1.leader=e2.dept_id and e1.name='张三丰';

    -- 3、查询出所有实习员工(实习员工无部门信息)
    select * from emp e left join dept d on e.dept_id = d.id where d.id is NULL;

  • XJJ_2020

    1、查询张姓员工的员工信息和所在部门信息。
    select * from emp left join dept on emp.dept_id = dept.id where emp.name like '张%'
    2、查询张三丰管理了几个员工
    select count(*) from emp e Inner join emp on e.id=emp.leader where emp.leader=1
    3、查询出所有实习员工(实习员工无部门信息)
    select * from emp left join dept on emp.dept_id = dept.id where dept.id is null

  • donghe

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